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PHP Pthreads – 使用mysqli

发布时间:2021-08-28 03:46:15 所属栏目:大数据 来源: https://www.jb51.cc
导读:我正在尝试在我的Web应用程序中首次使用pthreads.我有pthreads为简单的测试用例工作,但是在pthreads中使用mysql查询时遇到了麻烦.这是我的PHP文件: class sqlThread extends Thread{ private $dbc; public $log; public $return; public function __constru

我正在尝试在我的Web应用程序中首次使用pthreads.我有pthreads为简单的测试用例工作,但是在pthreads中使用mysql查询时遇到了麻烦.这是我的PHP文件:

class sqlThread extends Thread
{
    private $dbc;
    public $log;
    public $return;

    public function __construct(){
        $this->dbc = MysqLi_connect("localhost", "root", "rootpassword", "my_database");

        $this->log = "<br>(".__LINE__.") construct finished.";
    }

    //gets called when thread is started
    public function run(){
        $val = $this->testsqlCall();

        $this->log .= "<br>(".__LINE__.") testsqlCall() has finished";

        $this->return = $val;
    }

    /**
     * testing sql queries
     */
    function testsqlCall(){

        $sql = "SELECT *
                FROM client_detail";

        $this->log .= "<br>(".__LINE__.") testsqlCall() - sql: ".$sql;

        $r= @MysqLi_query($this->dbc,$sql);
        $num = MysqLi_affected_rows($this->dbc);

        $this->log .= "<br>(".__LINE__.") testsqlCall() - total number of returned rows: ".$num;

        return $num;

    }
}

/**
 * threaded test
 */
$thread = new sqlThread();
$thread->start();
$thread->join();

echo "<br><br><br>thread return value:";
var_dump($thread->return);
echo $thread->log;

/**
 * same test, but not threaded
 */

$dbc = MysqLi_connect("localhost", "root", "rootpassword", "my_database");
$sql = "SELECT *
        FROM client_detail";
$r = @MysqLi_query($dbc,$sql);
$num = MysqLi_affected_rows($dbc);
echo "<br><br> --- non-threaded return value: $num";

这是它的回报:

thread return value:

null


(12) construct finished.
(32) testsqlCall() - sql: SELECT * FROM client_detail
(37) testsqlCall() - total number of returned rows:
(19) testsqlCall() has finished

--- non-threaded return value: 39276

正如您所看到的,sqlThread中的MysqLi查询不返回任何内容,而sqlThread类之外的完全相同的查询返回我期望的内容.

有任何想法吗?有没有人在PHP线程中获得SQL查询才能工作?

解决方法:

问题是MysqLi对象不适合在多个线程中使用,你想为你启动的每个线程创建一个MysqLi实例,所以每个线程都有一个唯一的连接.

<?PHP
define("sqlHOST", "localhost");
define("sqlUSER", "root");
define("sqlPASS", "");
define("sqlDB",   "test");
define("sqlPORT", 3306);
define("sqlSOCK", "/var/lib/MysqL/MysqL.sock");

class Mine extends Thread {
    public function run() {
        try {
            $my = new MysqLi(sqlHOST, sqlUSER, sqlPASS, sqlDB, sqlPORT, sqlSOCK);
            if ($my) {
                $result = $my->query("SHOW DATABASES;");

                if (is_object($result)) {
                    while (($row = $result->fetch_assoc())) {
                        var_dump($row);
                    }
                }
            }
        } catch(Exception $ex) {
            var_dump($ex);
        }
    }
}

$mine = new Mine();
$mine->start();
?>

产量

array(1) {
  ["Database"]=>
  string(18) "information_schema"
}
array(1) {
  ["Database"]=>
  string(5) "MysqL"
}
array(1) {
  ["Database"]=>
  string(18) "performance_schema"
}
array(1) {
  ["Database"]=>
  string(4) "test"
}

请注意,MysqLi对象永远不会存储在Threads对象作用域中,因为您只应存储在您要共享的对象作用域中,并且由于您无法共享MysqLi连接,因此最好在方法作用域中对其进行操作.

github上有很多例子,包括一个sqlWorker示例,你应该全部阅读它们.

进一步阅读:https://gist.github.com/krakjoe/6437782

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