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php – 设置随机播放,不重复

发布时间:2021-08-28 03:48:48 所属栏目:大数据 来源: https://www.jb51.cc
导读:我有一个闪存卡阵列,并使用shuffle我输出15个独特的卡,每个卡3个不同的类别. 我想要做的是在同一个网页上为大约十几个人创建这些卡片组,但我无法弄清楚的部分是如何制作它,这样每个完整的套装都是独一无二的,并且不会从给定的套装中重复对任何其他用户. 一个

我有一个闪存卡阵列,并使用shuffle我输出15个独特的卡,每个卡3个不同的类别.

我想要做的是在同一个网页上为大约十几个人创建这些卡片组,但我无法弄清楚的部分是如何制作它,这样每个完整的套装都是独一无二的,并且不会从给定的套装中重复对任何其他用户.

一个带有简短说明的简短代码示例对我最有帮助.

这是我根据自己的需要修改的代码.真的没什么变化.

<?PHP
/* original source:
 * 3d10-engine.PHP
 * by Duane Brien
 */

if (empty($_POST)) {
for ($i = 1; $i < 16; $i++) {
    $numbers['ALL'][] = $i;
}

$picks = array();


$letters = array ('ALL');
foreach ($letters as $letter) {
    for ($i = 0;$i < 10;$i++) {
        shuffle($numbers[$letter]);
        $chunks = array_chunk($numbers[$letter], 5);
        $cards[$i][$letter] = $chunks[0];
        if ($letter == 'N') {
            $cards[$i][$letter][2] = '  '; // Free Space
        }

    }
    foreach ($numbers[$letter] as $number) {
        $balls[] = $letter.$number;
    }
    shuffle($balls);
}

$cardsstr = serialize($cards);
$ballsstr = serialize($balls);
$picksstr = serialize($picks);

} else {
$cards = unserialize($_POST['cardsstr']);
$balls = unserialize($_POST['ballsstr']);
$picks = unserialize($_POST['picksstr']);
array_unshift($picks, array_shift($balls));

echo "<h1>Just Picked: " . $picks[0] . "</h1>";

$cardsstr = serialize($cards);
$ballsstr = serialize($balls);
$picksstr = serialize($picks);
}

?>
Picks : <?PHP echo implode(',', $picks) ?>
<form method='post'>
<input type='hidden' name='cardsstr' value='<?PHP echo $cardsstr ?>' />
<input type='hidden' name='ballsstr' value='<?PHP echo $ballsstr ?>' />
<input type='hidden' name='picksstr' value='<?PHP echo $picksstr ?>' />
<input type='submit' name='cards' value='next number' />
</form>
<a href="3d10-engine.PHP">Start Over</a>
<?PHP

foreach ($cards as $card) {
echo "<table border='1'>";
echo "<tr><td>A</td><td>B</td><td>C</td><td>D</td><td>E</td></tr>";
for ($i = 0; $i < 5; $i++) {
    echo "<tr><td>" . $card['B'][$i] . "</td><td>" .$card['I'][$i]  . "</td><td>" . $card['N'][$i] . "</td>";
    echo "<td>" . $card['G'][$i] . "</td><td>" . $card['O'][$i] . "</td></tr>";
}
echo "</table>";
}

?>

解决方法:

由于每组中有更多选项,因此随机选择足以实现独特的最终结果.
我的意思是不要让这件事变得更复杂.

试试这个样本

<?PHP
//Initialize your 5 sets here
$numbers['B'] = range(1,15);
$numbers['I'] = range(16,30);
$numbers['N'] = range(31,45);
$numbers['G'] = range(45,60);
$numbers['O'] = range(61,75);

//My Assumption is you to pick 3 from each 

while(TRUE){
 $rand = rand(0,5);
 if(count($numbers_B) < 3 && !in_array($numbers['B'][$rand]){
   $numbers_B[] = $numbers['B'][$rand];
 }

 $rand = rand(0,5);
 if(count($numbers_I) < 3 && !in_array($numbers['I'][$rand]){
   $numbers_I[] = $numbers['I'][$rand];
 }
 $rand = rand(0,5);
 if(count($numbers_N) < 3 && !in_array($numbers['N'][$rand]){
   $numbers_N[] = $numbers['N'][$rand];
 }
 $rand = rand(0,5);
 if(count($numbers_G) < 3 && !in_array($numbers['G'][$rand]){
   $numbers_G[] = $numbers['G'][$rand];
 }
 $rand = rand(0,5);
 if(count($numbers_O) < 3 && !in_array($numbers['O'][$rand]){
   $numbers_O[] = $numbers['O'][$rand];
 }

if( count($numbers_B) == 3 && count($numbers_I) == 3 && count($numbers_N) == 3 && 

count($numbers_G) == 3 && count($numbers_O) == 3 ){
  break;
 }
    }
    $result = $numbers_B + $numbers_I + $numbers_N + $numbers_G + $numbers_O; ?>

这里$result值应该是唯一的,我认为集合的数量是不变的.如果它是动态的,那么尝试使用二维数组的相同逻辑.

(编辑:北几岛)

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