java编程思想第四版第十三章字符串习题

发布时间：2021-05-21 06:09:33 所属栏目：大数据来源： https://www.jb51.cc

导读：fas 第二题 package net.mindview.strings;import java.util.ArrayList;import java.util.List; /* * * 无限循环 */ public class InfiniteRecursion { public InfiniteRecursion(){ } @Override String toString() { return " InfiniteRecursion address "

第二题

package net.mindview.strings;

import java.util.ArrayList;
import java.util.List;

/**
 * 无限循环
 */
public class InfiniteRecursion {
    public InfiniteRecursion(){
        
    }
    @Override
     String toString() {
        return " InfiniteRecursion address" + super.toString() + n";
    }
    static void main(String[] args) {
        List<InfiniteRecursion> list = new ArrayList<InfiniteRecursion>();
        for(int i=0; i<5; i++){
            list.add(new InfiniteRecursion());
        }
        System.out.println(list);
    }
}

第四题

package net.mindview.strings;

import java.util.Formatter;

 Receipt {
    private double total = 0;
    private Formatter f = new Formatter(System.);
    public final int ITEM_WIDTH = 15int QTY_WIDTH = 5int PRICE_WIDTH = 10int PRICISION_FLOAT_WIDHT = 2int PRICISION_String_WIDHT = public final String TITLE_FORMAT = %-" + ITEM_WIDTH + s %" + QTY_WIDTH
            + " + PRICE_WIDTH + snpublic final String PRICE_FORMAT = ."
            + PRICISION_String_WIDHT + " + QTY_WIDTH + d % PRICE_WIDTH
            + " + PRICISION_FLOAT_WIDHT + fn; 
    public final String TOTAL_FORMAT = ; 
    
    //打印标题
     printTitle(){
        
         * 含义: 格式化字符串串以%开头
         * -: 表示左对齐
         * 15: 15表示宽度
         * s:表示数据的类型是String
         * .2f:表示浮点数保留的小数位数
         * .15s:表示字符串的长度最多15个字符 
         */
        f.format(TITLE_FORMAT,Item",QtyPrice);
        f.format(TITLE_FORMAT,1)">------------);
    }
    
    正文的内容
    void print(String name,int qty,1)">double price){
        f.format(PRICE_FORMAT,name,qty,price);
        total += price;
    }
    
    总价
     printTotal(){
        f.format(TOTAL_FORMAT,1)">Tax"",total*0.06);
        f.format(TOTAL_FORMAT,1)">Total1.06 main(String[] args) {
        Receipt receipt =  Receipt();
        receipt.printTitle();
        receipt.print(Jack`s Magic Beans4,1)">4.25);
        receipt.print(Princess Peas3,1)">5.1Three Bears Porridge1,1)">14.29);
        receipt.printTotal();
    }

}

运行结果：

Item              Qty      Price
----              ---      -----
Jack`s Magic Be     4       
Princess Peas       3       5.10
Three Bears Por     1      
Tax                         1.42
                           -----
Total                      25.06

第五题

);
        receipt.printTotal();
    }

}

运行结果:

25.06

第七题:

package net.mindview.strings.test7;

 Test7 {

     main(String[] args) {
        两种写法都可以
        String regex = ^[A-Z].*.$;
        String regex1 = p{Upper}.*.$;
        String str = D.;
        String str1 = Dfasdfasfasfdasfdasfasfasdf.;
        String str2 = Dfasdfasfasfdasfdasfasfasdf.E;
        System..println(str.matches(regex));
        System..println(str1.matches(regex));
        System..println(str2.matches(regex));
        System..println(str.matches(regex1));
        System..println(str1.matches(regex1));
        System..println(str2.matches(regex1));
    }
}

运行结果:

true
false
false

第八题

package net.mindview.strings;

import java.util.Arrays;

 Splitting {

    static String knights = Then,when you have found the shrubbery,you must cut down the mightiest tree in the forest... with... a herring!;

     split(String regex){
        System..println(Arrays.toString(knights.split(regex)));
    }
    表示的时按照空格分割字符串
        运行结果:[Then,when,you,have,found,the,shrubbery,must,cut,down,mightiest,tree,in,forest...,with...,a,herring!]
        split(" );
        
        表示按照非单次字符分割字符串--这里的非单次字符是空格和,W+);
        这个表示:费单次字符之前带n的地方进行分割字符串 这里的分割符是n空格和n,1)">运行结果:[The,whe,you have found the shrubbery,you must cut dow,the mightiest tree i,the forest... with... a herring!]
        split(nW+);
    }

}

package net.mindview.strings.test8;

import net.mindview.strings.Splitting;

 Test8 {
    
     main(String[] args) {
        String regex = the|you;
        Splitting.split(regex);
    }
}

第九题

package net.mindview.strings.test9;

import net.mindview.strings.Splitting;

 Test9 {
    A|E|I|O|U|a|e|i|o|u;
        通过嵌入式标志表达式  (?i) 也可以启用不区分大小写的匹配。
        String regex1 = (?i)a|e|i|o|u[abc] 表示a或b或c
        String regex2 = (?i)[aeIoU]out.println(Splitting.knights.replaceAll(regex,1)">_));
        System.out.println(Splitting.knights.replaceAll(regex1,1)">out.println(Splitting.knights.replaceAll(regex2,1)">));
    }
}

第十题

package net.mindview.strings.test10;

import java.util.regex.Matcher;
import java.util.regex.Pattern;

 Test10 {
     main(String[] args) {
        String str = Java now has regular expressions;
        
        for(String arg: args){
            Pattern p = Pattern.compile(arg);
            Matcher m = p.matcher(str);
            while(m.find()){
                System.out.println(Match "" + m.group() +" at positions " + m.start() + -" + (m.end()-1) );
            }
            System.);
        }
        
    }
}

输入参数:

^Java
Breg.*
n.ws+h(a|i)s
s?
s*
s+
s{4}
s{}.
s{0,1)">3}

输出结果

Match Java" at positions 0-3




Match now has5-11


Match "" at positions 0--
Match 1-2-3-4-6-7-68-79-810-9s11-12-13-1214-1315-1416-17-1618-1719-1820-1921-2022-2123-2224-2325-2426-2627-2728-29-2830-2931-3132-sss 31

第十一题

package net.mindview.strings.test11;

import java.util.regex.Matcher;
import java.util.regex.Pattern;

 Test11 {
     main(String[] args) {
        Pattern p = Pattern.compile((?i)((^[aeIoU])|(s+[aeIoU]))w+?[aeIoU]b);
        Matcher m = p.matcher(Arline ate eight apples and " +
one orange while Anita hadn't any(m.find()){
            System." + m.group() +
                    
                    (m.end() - ));
        }
    }
}

运行结果:

Match Arline ate one30 orange37 Anita44-49

sfa
f
a
fda
sdf
af
a
fd
af
as
fd
asfd
af
da
f
df
as
fa
sf
asf
a
sf
af
asf

（编辑：北几岛）

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java编程思想第四版第十三章字符串 习题

java编程思想第四版第十三章字符串习题